Question:

HTML/PHP Programming Question

I would like to get your expert opinion on a time estimate for a programming task.

The task involves modifying a PHP and HTML website that queries an SQL database and displays the following table:

Firstname | lastname | company | date

———–|———-|———-|———

David | Davidson | David Inc. | Jan 2016

John | Johnson | John Inc. | Jan 2017

Jack | Jackson | Jack Inc. | Null

Total Record Count: 3

The modification requires adding three more counts after the total record count:

• Total records with date in the past
• Total records with date in the present/future
• Total records with no date

How long do you think it would take for the programmer who coded the website to implement this modification? Please provide a rough estimate and explain your reasoning.

“`

Answer:

HTML/PHP Programming Question

Answer:

The time estimate for the programming task depends on several factors, such as the complexity of the SQL query, the structure of the database, the size of the data, and the skill level of the programmer. However, assuming that the programmer is familiar with the code and the database, and that the data is not too large, a rough estimate could be as follows:

to write and test, depending on the format and logic of the date column. A possible query could be:

“`sql

SELECT

COUNT(CASE WHEN date IS NULL THEN 1 END) AS no_date_count, COUNT(CASE WHEN date < CURDATE() THEN 1 END) AS past_date_count, COUNT(CASE WHEN date >= CURDATE() THEN 1 END) AS future_date_count

FROM table_name;

“`

– Modifying the PHP code to execute the query and display the results: This could take about

15 minutes

to modify and test, depending on the structure and style of the PHP code. A possible modification could be:

“`php SELECT

COUNT(CASE WHEN date IS NULL THEN 1 END) AS no_date_count, COUNT(CASE WHEN date < CURDATE() THEN 1 END) AS past_date_count, COUNT(CASE WHEN date >= CURDATE() THEN 1 END) AS future_date_count

FROM table_name”;

$result = $conn->query($sql); // Fetch the query result and store it in variables $row = $result->fetch_assoc(); $no_date_count = $row[“no_date_count”]; $past_date_count = $row[“past_date_count”]; $future_date_count = $row[“future_date_count”]; // Display the original table and the total record count

echo “

“;

echo “

“;

echo “

“;

echo “

“;

echo “

“;

echo “

“;

echo “

Firstname | lastname | company | date

———–|———-|———-|———

David | Davidson | David Inc. | Jan 2016

John | Johnson | John Inc. | Jan 2017

Jack | Jackson | Jack Inc. | Null

“;

echo “Total Record Count: ” . $result->num_rows;

// Display the additional counts based on the date condition

echo “Total records with date in the past: ” . $past_date_count;

echo “Total records with date in the present/future: ” . $future_date_count;

echo “Total records with no date: ” . $no_date_count;

?>
“`

– Deploying the modified code to the website: This could take about

5 minutes

to upload and test, depending on the hosting service and the deployment method.

Therefore, the total time estimate for the programming task could be around

30 minutes

. However, this is only a rough estimate and it could vary depending on the actual situation and the programmer’s experience. It is always advisable to add some buffer time for debugging and unexpected issues.

“`